Data Layout in Matrix

Repost from an earlier question. I am trying to use a matrix to display records in three columns per row, like this:
Record1 Record2 Record3
Model Model Model
Descript Descript Descript
Price Price Price
Unable to get the dynamic columns expanding to the right, or set the # of columns.
Below is the conversation so far...
Any help would be greatly appreciated!
---
Thank you for the response Chris. I've been out and unable to test this until today. I set it up as you suggested - I have a matrix with two three static rows and a column group on =RowNumber(Nothing).
I get the following error message:
"A group expression for the grouping â'matrix1_ColumnGroup1â' uses the RowNumber function with a scope parameter that is not valid. When used in a group expression, the value of the scope parameter of RowNumber must equal the name of the group directly containing the current group."
Using the List group name as the RowNumber parameter throws more errors.
What am I missing?
Michael
"Chris Hays [MSFT]" wrote:
> You'll need to use a matrix to get a horizontially growing layout.
> It should have one dynamic column grouping (group on =RowNumber(Nothing))
> and three static rows (right-click in the data area and select "Add Row"
> twice).
> To limit this to three columns per matrix, put the matrix in a list and
> group on something like this: =Ceiling(RowNumber(Nothing)/3)
>
> --
> This post is provided 'AS IS' with no warranties, and confers no rights. All
> rights reserved. Some assembly required. Batteries not included. Your
> mileage may vary. Objects in mirror may be closer than they appear. No user
> serviceable parts inside. Opening cover voids warranty. Keep out of reach of
> children under 3.
> "OTB6" <OTB6@.discussions.microsoft.com> wrote in message
> news:7EC2C1E0-98C2-4069-B951-D40123C37ABF@.microsoft.com...
> > Trying to find a way to display returned records in (n) rows of 3 columns
> or less like this:
> >
> > Record 1 Record 2 Record 3
> > col 1 col 1 col 1
> > col 2 col 2 col 2
> > col 3 col 3 col 3
> >
> > Record 4 Record 5
> > col 1 col 1
> > col 2 col 2
> > col 3 col 3
> >
> > Can someone point me in the right direction as far as the tools
> (table/matrix/list)?
> >
> > Thanks!
> >
> > Michael<-- okay really feeling like an idiot now, but...
where/how is this attachment retrieved? if sent to the email listed in my profile, I'm not receiving it. I'd REALLY like to see your solution.
m
"Chris Hays [MSFT]" wrote:
> Using the list group name should have worked.
> I'm attaching a working example so you can compare to what you've done to
> find where they differ.
>|||You really should use a real newsreader (like Outlook Express) so you can
receive and post attachments.
(Most web-based newsreaders fail to implement support for attachments.)
I'll be posting this example to my weblog later today so you'll be able to
get it there if you can't use a real newsreader for some reason:
http://blogs.msdn.com/chrishays
--
This post is provided 'AS IS' with no warranties, and confers no rights. All
rights reserved. Some assembly required. Batteries not included. Your
mileage may vary. Objects in mirror may be closer than they appear. No user
serviceable parts inside. Opening cover voids warranty. Keep out of reach of
children under 3.
"OTB6" <OTB6@.discussions.microsoft.com> wrote in message
news:8994534E-8F27-4102-832A-071AEC7D1978@.microsoft.com...
> <-- okay really feeling like an idiot now, but...
> where/how is this attachment retrieved? if sent to the email listed in my
profile, I'm not receiving it. I'd REALLY like to see your solution.
> m
> "Chris Hays [MSFT]" wrote:
> > Using the list group name should have worked.
> > I'm attaching a working example so you can compare to what you've done
to
> > find where they differ.
> >
>